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Find an Armstrong Number in Java

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Find an Armstrong Number in Java

In this example, we will see a Java program through which we will find if a given input number is an Armstrong number or not.

Any given positive number can be an Armstrong number if it is equal to the sum of the cubes of its digits for example 0, 1, 153, etc.

Program


class Main
{  
  public static void main(String[] args)  
  {  
    int c=0,a,temp;  
    int n=407;//It is the number to check armstrong  
    temp=n;  
    while(n>0)  
    {  
    a=n%10;  
    n=n/10;  
    c=c+(a*a*a);  
    }  
    if(temp==c)  
    System.out.println("Given number is armstrong number");   
    else  
    System.out.println("Not armstrong number");   
   }  
}

Output:
Given number is armstrong number

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