Check Palindrome Number in Java

Check Palindrome Number in Java

In this example, we will see a Java program through which we will check if the given input number or string is a Palindrome or not.

A given number is said to be a palindrome number if that number is the same after reverse. For example 545, 151, 34543 are the palindrome numbers.

Algorithm:

• STEP 1 : Get the number to check for the palindrome.
• STEP 2 : Hold the number in a temporary variable.
• STEP 3 : Reverse that number.
• STEP 4 : Compare the temporary number with the reversed number.
• STEP 5 : If both numbers are the same, print "palindrome number".
• STEP 6 : Else print "not palindrome number".

class Main
{  
 public static void main(String args[])
 {  
  int r,sum=0,temp;    
  int n=872232278;//It is the number variable to be checked for palindrome  
  
  temp=n;    
  while(n>0)
  {    
   r=n%10;  //getting remainder  
   sum=(sum*10)+r;    
   n=n/10;    
  }    
  if(temp==sum)    
  System.out.println("Given nuumber is Palindrome ");    
  else    
  System.out.println("not palindrome");    
}  
}  

Palindrome Program in Java(Different way)

import java.util.*;   
class Main
{  
   public static void main(String args[])  
   {  
      String original, reverse = ""; // Objects of String class  
      Scanner in = new Scanner(System.in);   
      System.out.println("Enter a string/number to check if it is a palindrome");  
      original = in.nextLine();   
      int length = original.length();   
      for ( int i = length - 1; i >= 0; i-- )  
         reverse = reverse + original.charAt(i);  
      if (original.equals(reverse))  
         System.out.println("Entered string/number is a palindrome.");  
      else  
         System.out.println("Entered string/number isn't a palindrome.");   
   }  
}